4y^2=-8y-1

Solution for 4y^2=-8y-1 equation:

4y^2=-8y-1

We move all terms to the left:

4y^2-(-8y-1)=0

We get rid of parentheses

4y^2+8y+1=0

a = 4; b = 8; c = +1;
Δ = b2-4ac
Δ = 82-4·4·1
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{3}}{2*4}=\frac{-8-4\sqrt{3}}{8}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{3}}{2*4}=\frac{-8+4\sqrt{3}}{8}
$